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Find Left Null Space Calculator – Calculator

Find Left Null Space Calculator






Left Null Space Calculator – Find Basis & Dimension


Left Null Space Calculator

Matrix Input & Calculator

Enter the dimensions of your matrix A (up to 4×4) and then its elements to find the left null space (null space of AT).


Enter the number of rows of matrix A.


Enter the number of columns of matrix A.

Enter the elements of matrix A row by row.



What is the Left Null Space?

The left null space of a matrix A is the set of all row vectors xT such that xTA = 0T (the zero row vector). It’s a vector subspace of the row space of A. An equivalent way to think about it is finding the null space of the transpose of A, denoted as AT. If xTA = 0T, then taking the transpose of both sides gives (xTA)T = (0T)T, which means ATx = 0. So, the left null space of A is the null space of AT, N(AT).

This left null space calculator helps you find a basis for the left null space of a given matrix A, and also determines its dimension. It’s useful for students and professionals in linear algebra, engineering, computer science, and data analysis.

Common misconceptions include confusing it with the regular null space (or right null space), which consists of column vectors y such that Ay = 0.

Left Null Space Formula and Mathematical Explanation

The left null space of an m x n matrix A is defined as the set of all row vectors xT (which are 1 x m) such that:

xTA = 0T

This is equivalent to finding the vectors x such that ATx = 0, where AT is the n x m transpose of A, and x is an m x 1 column vector. So, the left null space of A is the null space of AT, N(AT).

To find the basis for the left null space of A (or N(AT)):

  1. Find the transpose of A, which is AT.
  2. Perform Gaussian elimination (row reduction) on AT to bring it to its Reduced Row Echelon Form (RREF).
  3. Identify the pivot columns and free columns in the RREF of AT.
  4. The number of free columns gives the dimension of the left null space of A (and the null space of AT).
  5. Express the pivot variables (corresponding to pivot columns) in terms of the free variables (corresponding to free columns).
  6. Write the general solution for ATx = 0 in vector form, and the vectors multiplying the free variables form a basis for the left null space of A.

The dimension of the left null space of an m x n matrix A is m – r, where r is the rank of A (which is also the rank of AT).

Variables in Left Null Space Calculation
Variable Meaning Type Typical Range
A The original matrix m x n matrix Elements can be any real numbers
AT The transpose of matrix A n x m matrix Elements from A
xT A row vector in the left null space 1 x m row vector Elements can be any real numbers
x A column vector in the null space of AT m x 1 column vector Elements can be any real numbers
r Rank of matrix A (and AT) Integer 0 to min(m, n)
m – r Dimension of the left null space of A Integer 0 to m

Practical Examples (Real-World Use Cases)

Example 1: A 2×3 Matrix

Let’s find the left null space for the matrix:

A = [[1, 2, 3], [4, 5, 6]]

1. Transpose A: AT = [[1, 4], [2, 5], [3, 6]]

2. Row reduce AT to RREF:

[[1, 4], [2, 5], [3, 6]] -> [[1, 4], [0, -3], [0, -6]] -> [[1, 4], [0, 1], [0, 0]] -> [[1, 0], [0, 1], [0, 0]]

3. RREF(AT) = [[1, 0], [0, 1], [0, 0]]. We have two pivot columns and no free columns. The variables are x1 and x2. Both are pivot variables. The equations are x1=0, x2=0. The only solution to ATx = 0 is x = [0, 0]T. So the left null space of A contains only the zero vector [0, 0]. The dimension is 0.

Example 2: A 3×2 Matrix with a Non-Trivial Left Null Space

Let A = [[1, 0], [2, 0], [0, 1]]

1. AT = [[1, 2, 0], [0, 0, 1]]

2. AT is already in RREF. Columns 1 and 3 are pivot columns (x1, x3 are pivot variables). Column 2 is free (x2 is free variable).

3. Equations: x1 + 2×2 = 0 => x1 = -2×2; x3 = 0. Let x2 = t (free parameter). Solution: x = [-2t, t, 0]T = t * [-2, 1, 0]T.

4. Basis for left null space of A (null space of AT): {[-2, 1, 0]T}. The dimension is 1.

Using our left null space calculator for A=[[1, 0], [2, 0], [0, 1]] would give basis {[ -2, 1, 0 ]T}.

How to Use This Left Null Space Calculator

  1. Enter Matrix Dimensions: Specify the number of rows (m) and columns (n) of your matrix A using the “Rows of A” and “Columns of A” input fields (max 4×4).
  2. Generate Matrix Inputs: The calculator will dynamically create input fields based on the dimensions you provided.
  3. Enter Matrix Elements: Fill in the numerical values for each element of matrix A.
  4. Calculate: Click the “Calculate Left Null Space” button.
  5. View Results: The calculator will display:
    • The original matrix A.
    • The transpose AT.
    • The Reduced Row Echelon Form (RREF) of AT.
    • A basis for the left null space of A (which is the basis for N(AT)).
    • The dimension of the left null space.
    • A chart visualizing the number of rows/columns of AT and its rank vs nullity.
    • A summary table.
  6. Reset: Click “Reset” to clear the inputs and start with default values.
  7. Copy: Click “Copy Results” to copy the key findings to your clipboard.

Key Factors That Affect Left Null Space Results

  • Matrix Elements: The specific numbers within the matrix A determine the linear dependencies among the rows of A (or columns of AT), which directly defines the left null space. Small changes can significantly alter the basis and dimension.
  • Matrix Dimensions (m x n): The number of rows (m) of A determines the number of components in the vectors of the left null space. The dimension of the left null space is m – rank(A).
  • Rank of the Matrix: The rank of A (number of linearly independent rows or columns) is crucial. A higher rank means a smaller dimension for the left null space. If rank(A) = m, the left null space is just the zero vector.
  • Linear Dependence of Rows: If some rows of A are linear combinations of others, this leads to zero rows in the row reduction of AT after transposing, giving rise to free variables and a non-trivial left null space.
  • Numerical Precision: When dealing with floating-point numbers, the precision of calculations during row reduction can affect whether a value is treated as zero, potentially influencing the identified pivot and free variables and thus the basis found by the left null space calculator.
  • Singularity (for square matrices): If A is a square matrix, whether it’s singular (determinant is zero) or non-singular affects its rank and thus the dimension of its left null space. A singular matrix will have a non-trivial left null space if m=n and rank < m.

Frequently Asked Questions (FAQ)

What is the difference between null space and left null space?
The null space (or right null space) of A consists of column vectors x such that Ax = 0. The left null space of A consists of row vectors xT such that xTA = 0T, or equivalently column vectors y such that ATy = 0.
Why is it called “left” null space?
Because the vector xT multiplies the matrix A from the left: xTA.
What is the dimension of the left null space?
For an m x n matrix A with rank r, the dimension of the left null space is m – r.
What if the left null space only contains the zero vector?
This means the dimension of the left null space is 0, and the rows of A are linearly independent (if m <= n and rank = m).
How do I find the basis of the left null space?
Find the null space of AT by row-reducing AT to RREF, identifying free variables, and expressing the solution vector in terms of these free variables. The vectors multiplying the free parameters form the basis. Our left null space calculator does this automatically.
Is the left null space always a vector space?
Yes, the left null space of any matrix is always a vector subspace of the row space’s dimension.
Can the left null space calculator handle any matrix size?
This specific calculator is designed for matrices up to 4×4 for practical web implementation. More advanced software can handle larger matrices.
What does a basis for the left null space tell me?
A basis is a set of linearly independent vectors that span the left null space. Any vector in the left null space can be written as a linear combination of the basis vectors.

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