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Find Left Null Space Of Matrix Calculator – Calculator

Find Left Null Space Of Matrix Calculator






Left Null Space of Matrix Calculator – Find N(A^T)


Left Null Space of Matrix Calculator


Matrix A will have m rows. (1-4)


Matrix A will have n columns. (1-4)



What is the Left Null Space of a Matrix?

The left null space of a matrix A, denoted as N(AT), is the set of all row vectors yT such that yTA = 0T (the zero row vector). Equivalently, it is the null space of the transpose of A, AT. That is, it’s the set of all column vectors y such that ATy = 0 (the zero column vector).

If A is an m x n matrix, its transpose AT is an n x m matrix. The left null space of A is a subspace of Rm (the space of m-dimensional row vectors, or n-dimensional column vectors if considering ATy=0). The dimension of the left null space of A is given by m – r, where r is the rank of A (which is also the rank of AT).

The left null space is one of the four fundamental subspaces associated with a matrix A, the others being the column space (C(A)), the null space (N(A)), and the row space (C(AT)). The row space and null space are orthogonal complements in Rn, while the column space and left null space are orthogonal complements in Rm.

Who should use it?

Students of linear algebra, engineers, scientists, and anyone working with systems of linear equations, vector spaces, or data analysis involving matrices often need to understand and find the left null space of a matrix. It’s crucial for understanding the relationships between the rows of a matrix and the solutions to linear systems.

Common Misconceptions

A common misconception is confusing the left null space (N(AT)) with the (right) null space (N(A)). The null space N(A) consists of vectors x such that Ax = 0, while the left null space N(AT) consists of vectors y such that ATy = 0 (or yTA = 0T).

Left Null Space of a Matrix Formula and Mathematical Explanation

To find the left null space of a matrix A (m x n), we follow these steps:

  1. Transpose the Matrix A: Find AT, which will be an n x m matrix.
  2. Set up the Homogeneous System: We want to solve ATy = 0, where y is a column vector with m components.
  3. Row Reduce AT: Perform Gaussian elimination on AT to transform it into its Reduced Row Echelon Form (RREF).
  4. Identify Pivot and Free Variables: In the RREF of AT, columns with leading 1s correspond to pivot variables, and columns without leading 1s correspond to free variables among the components of y.
  5. Express Pivot Variables: Write the pivot variables in terms of the free variables from the equations represented by the RREF of AT.
  6. Form Basis Vectors: Construct the basis vectors for the null space of AT by setting each free variable to 1 (and others to 0) one at a time and finding the corresponding values of the pivot variables. These vectors span the left null space of matrix A.

The dimension of the left null space is equal to the number of free variables in the system ATy = 0, which is m – rank(AT) = m – rank(A).

Variables Table

Variable Meaning Unit Typical range
A The original m x n matrix Matrix Real numbers
AT The transpose of A (n x m matrix) Matrix Real numbers
m Number of rows of A Integer ≥ 1
n Number of columns of A Integer ≥ 1
r Rank of A (and AT) Integer 0 ≤ r ≤ min(m, n)
dim(N(AT)) Dimension of the left null space Integer m – r
y Vector in the left null space (m x 1) Vector Real numbers

The table above summarizes the key elements when working with the left null space of a matrix.

Practical Examples (Real-World Use Cases)

Example 1: Finding the Left Null Space

Let’s consider matrix A:


A = [[1, 2, 3],
[4, 5, 6]]

Here, m=2, n=3. A is 2×3.

1. Transpose A:


AT = [[1, 4],
[2, 5],
[3, 6]]

AT is 3×2.

2. Solve ATy = 0. We row reduce AT:


[[1, 4], R2 = R2 - 2R1 [[1, 4], R3 = R3 - 3R1 [[1, 4], R2 = -1/3 * R2 [[1, 4], R1=R1-4R2 [[1, 0],
[2, 5], ---------> [0,-3], ---------> [0,-3], ----------> [0, 1], --------> [0, 1],
[3, 6]] [3, 6]] [0,-6]] [0,-6]] R3=R3+6R2 [0, 0]]

RREF(AT) is [[1, 0], [0, 1], [0, 0]]. Both columns are pivot columns. There are no free variables. The only solution to ATy = 0 is y = [0, 0]T. So, the left null space of A is just the zero vector {0}, and its dimension is 0. (m-r = 2-2=0)

Example 2: A Matrix with a Non-trivial Left Null Space

Let’s consider matrix A:


A = [[1, 0, 1],
[2, 0, 2]]

Here m=2, n=3.

1. Transpose A:


AT = [[1, 2],
[0, 0],
[1, 2]]

AT is 3×2.

2. Solve ATy = 0 for y=[y1, y2, y3]T, which isn’t right. y is m x 1, so y=[y1, y2]T. AT is 3×2, y is 2×1. So we solve ATy = 0 where y = [y1, y2]T. Wait, A is m x n, AT is n x m (3×2), y must be m x 1 (2×1).
Let’s recheck the definition: yTA = 0T, yT is 1xm, so y is mx1. So y = [y1, y2]T.
ATy = 0 where AT is 3×2 and y is 2×1.
[[1, 2], [0, 0], [1, 2]] [y1, y2]T = [0,0,0]T
y1 + 2y2 = 0
0 = 0
y1 + 2y2 = 0
RREF of AT: [[1, 2], [0, 0], [0, 0]]. Rank = 1.
y1 = -2y2. y2 is free. Let y2=t, y1=-2t. y = [-2t, t]T = t[-2, 1]T.
The left null space is spanned by [-2, 1]T or row vector [-2, 1]. Dimension = m-r = 2-1 = 1.

Let’s take a 3×3 matrix A to have a non-trivial left null space more clearly.


A = [[1, 2, 3],
[0, 1, 1],
[1, 3, 4]]

m=3, n=3.
AT = [[1, 0, 1], [2, 1, 3], [3, 1, 4]]
Row reduce AT:
[[1, 0, 1], R2=R2-2R1 [[1, 0, 1], R3=R3-3R1 [[1, 0, 1], R3=R3-R2 [[1, 0, 1],
[2, 1, 3], ——–> [0, 1, 1], ——–> [0, 1, 1], ——–> [0, 1, 1],
[3, 1, 4]] [0, 1, 1]] [0, 1, 1]] [0, 0, 0]]
RREF(AT) = [[1, 0, 1], [0, 1, 1], [0, 0, 0]]. Rank=2. Dimension of left null space = m-r = 3-2 = 1.
ATy = 0 gives: y1 + y3 = 0, y2 + y3 = 0. y3 is free.
y1 = -y3, y2 = -y3. Let y3=t. y = [-t, -t, t]T = t[-1, -1, 1]T.
Basis for left null space: {[-1, -1, 1]T}.

How to Use This Left Null Space of a Matrix Calculator

  1. Enter Matrix Dimensions: Select the number of rows (m) and columns (n) for your matrix A using the dropdowns. The calculator supports matrices up to 4×4.
  2. Input Matrix Elements: Enter the numerical values for each element of matrix A into the generated input fields. Ensure you enter valid numbers.
  3. Calculate: Click the “Calculate Left Null Space” button.
  4. View Results: The calculator will display:
    • The original matrix A.
    • The transpose AT.
    • The Reduced Row Echelon Form (RREF) of AT.
    • The rank of AT.
    • The basis vectors for the left null space of matrix A.
    • The dimension of the left null space (m – rank(AT)).
    • A chart visualizing the dimensions, rank, and nullity.
  5. Interpret Basis: The basis vectors form a set of linearly independent vectors that span the left null space. Any vector in the left null space can be written as a linear combination of these basis vectors.
  6. Reset: Click “Reset” to clear the inputs and results and start with default values.
  7. Copy: Click “Copy Results” to copy the main results and intermediate values to your clipboard.

Understanding the dimension of the left null space of a matrix is key; if it’s 0, only the zero vector is in it.

Key Factors That Affect Left Null Space Results

  • Matrix Dimensions (m and n): The number of rows (m) of A determines the dimension of the space Rm where the left null space resides and influences its maximum possible dimension.
  • Rank of the Matrix (r): The rank of A (and AT) directly determines the dimension of the left null space (m-r). A higher rank means a smaller left null space dimension.
  • Linear Independence of Rows of A: The rows of A form the columns of AT. If the rows of A are linearly independent (when m ≤ n), the rank of AT is m, and the left null space is trivial ({0}). If rows are dependent, the rank is less than m, and the left null space is non-trivial.
  • Values of Matrix Elements: The specific numbers in the matrix determine the relationships between the rows and thus the structure and basis of the left null space of the matrix after row reduction.
  • Number of Free Variables: When solving ATy = 0, the number of free variables after row reduction equals the dimension of the left null space.
  • Pivots in RREF(AT): The positions of the pivot elements in the RREF of AT identify the pivot variables, which are expressed in terms of the free variables to find the basis vectors.

Frequently Asked Questions (FAQ)

What is the left null space of a matrix A?
It’s the set of all row vectors yT such that yTA = 0T, or equivalently, the null space of AT, containing all column vectors y such that ATy = 0.
How is the left null space different from the null space?
The left null space N(AT) involves AT (or multiplying A from the left by a row vector), while the null space N(A) involves A and multiplying A from the right by a column vector (Ax=0).
What is the dimension of the left null space?
If A is m x n, the dimension of its left null space is m – r, where r is the rank of A.
Why is it called the ‘left’ null space?
Because it involves vectors that multiply A from the left (yTA = 0T). It’s associated with the rows of A.
What does it mean if the left null space only contains the zero vector?
It means the rows of matrix A are linearly independent (if m ≤ n and rank=m), and the only linear combination of rows that gives the zero row is the trivial one (all coefficients zero).
How is the left null space related to the column space?
The left null space of A is the orthogonal complement of the column space of A in Rm.
Can any matrix have a non-trivial left null space?
Yes, if the rows of the matrix A are linearly dependent (rank(A) < m), then the left null space will have a dimension greater than zero and be non-trivial.
How do I find a basis for the left null space?
Find the RREF of AT, solve ATy=0, identify free variables, and express the solution in terms of these free variables to get the basis vectors using our left null space of matrix calculator.

Related Tools and Internal Resources

These tools, including the find left null space of matrix calculator, are valuable for understanding linear algebra concepts.

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